9(y+10)+3(y+6)=228

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Solution for 9(y+10)+3(y+6)=228 equation: 



9(y+10)+3(y+6)=228

We move all terms to the left:

9(y+10)+3(y+6)-(228)=0

We multiply parentheses

9y+3y+90+18-228=0

We add all the numbers together, and all the variables

12y-120=0

We move all terms containing y to the left, all other terms to the right

12y=120

y=120/12

y=10

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