9(y+10)+y=4(y+3)+7

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Solution for 9(y+10)+y=4(y+3)+7 equation: 



9(y+10)+y=4(y+3)+7

We move all terms to the left:

9(y+10)+y-(4(y+3)+7)=0

We add all the numbers together, and all the variables

y+9(y+10)-(4(y+3)+7)=0

We multiply parentheses

y+9y-(4(y+3)+7)+90=0



We calculate terms in parentheses: -(4(y+3)+7), so:

4(y+3)+7

We multiply parentheses

4y+12+7

We add all the numbers together, and all the variables

4y+19

Back to the equation:

-(4y+19)



We add all the numbers together, and all the variables

10y-(4y+19)+90=0

We get rid of parentheses

10y-4y-19+90=0

We add all the numbers together, and all the variables

6y+71=0

We move all terms containing y to the left, all other terms to the right

6y=-71

y=-71/6

y=-11+5/6

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