9(y+2)-3=6(2y-3)

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Solution for 9(y+2)-3=6(2y-3) equation: 



9(y+2)-3=6(2y-3)

We move all terms to the left:

9(y+2)-3-(6(2y-3))=0

We multiply parentheses

9y-(6(2y-3))+18-3=0



We calculate terms in parentheses: -(6(2y-3)), so:

6(2y-3)

We multiply parentheses

12y-18

Back to the equation:

-(12y-18)



We add all the numbers together, and all the variables

9y-(12y-18)+15=0

We get rid of parentheses

9y-12y+18+15=0

We add all the numbers together, and all the variables

-3y+33=0

We move all terms containing y to the left, all other terms to the right

-3y=-33

y=-33/-3

y=+11

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