9(y+2)=3y+42

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Solution for 9(y+2)=3y+42 equation: 



9(y+2)=3y+42

We move all terms to the left:

9(y+2)-(3y+42)=0

We multiply parentheses

9y-(3y+42)+18=0

We get rid of parentheses

9y-3y-42+18=0

We add all the numbers together, and all the variables

6y-24=0

We move all terms containing y to the left, all other terms to the right

6y=24

y=24/6

y=4

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