9(y+2)=3y+42

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Solution for 9(y+2)=3y+42 equation:



9(y+2)=3y+42
We move all terms to the left:
9(y+2)-(3y+42)=0
We multiply parentheses
9y-(3y+42)+18=0
We get rid of parentheses
9y-3y-42+18=0
We add all the numbers together, and all the variables
6y-24=0
We move all terms containing y to the left, all other terms to the right
6y=24
y=24/6
y=4

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