9(y+2)=6(y-3)

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Solution for 9(y+2)=6(y-3) equation: 



9(y+2)=6(y-3)

We move all terms to the left:

9(y+2)-(6(y-3))=0

We multiply parentheses

9y-(6(y-3))+18=0



We calculate terms in parentheses: -(6(y-3)), so:

6(y-3)

We multiply parentheses

6y-18

Back to the equation:

-(6y-18)



We get rid of parentheses

9y-6y+18+18=0

We add all the numbers together, and all the variables

3y+36=0

We move all terms containing y to the left, all other terms to the right

3y=-36

y=-36/3

y=-12

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