9(y+4)=5y+48

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Solution for 9(y+4)=5y+48 equation: 



9(y+4)=5y+48

We move all terms to the left:

9(y+4)-(5y+48)=0

We multiply parentheses

9y-(5y+48)+36=0

We get rid of parentheses

9y-5y-48+36=0

We add all the numbers together, and all the variables

4y-12=0

We move all terms containing y to the left, all other terms to the right

4y=12

y=12/4

y=3

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