9(y+4)=6y+33

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Solution for 9(y+4)=6y+33 equation:



9(y+4)=6y+33
We move all terms to the left:
9(y+4)-(6y+33)=0
We multiply parentheses
9y-(6y+33)+36=0
We get rid of parentheses
9y-6y-33+36=0
We add all the numbers together, and all the variables
3y+3=0
We move all terms containing y to the left, all other terms to the right
3y=-3
y=-3/3
y=-1

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