9(y+4)=6y+33

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Solution for 9(y+4)=6y+33 equation: 



9(y+4)=6y+33

We move all terms to the left:

9(y+4)-(6y+33)=0

We multiply parentheses

9y-(6y+33)+36=0

We get rid of parentheses

9y-6y-33+36=0

We add all the numbers together, and all the variables

3y+3=0

We move all terms containing y to the left, all other terms to the right

3y=-3

y=-3/3

y=-1

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