9(y+5)+y=3(y+4)+4

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Solution for 9(y+5)+y=3(y+4)+4 equation: 



9(y+5)+y=3(y+4)+4

We move all terms to the left:

9(y+5)+y-(3(y+4)+4)=0

We add all the numbers together, and all the variables

y+9(y+5)-(3(y+4)+4)=0

We multiply parentheses

y+9y-(3(y+4)+4)+45=0



We calculate terms in parentheses: -(3(y+4)+4), so:

3(y+4)+4

We multiply parentheses

3y+12+4

We add all the numbers together, and all the variables

3y+16

Back to the equation:

-(3y+16)



We add all the numbers together, and all the variables

10y-(3y+16)+45=0

We get rid of parentheses

10y-3y-16+45=0

We add all the numbers together, and all the variables

7y+29=0

We move all terms containing y to the left, all other terms to the right

7y=-29

y=-29/7

y=-4+1/7

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