9(y+7)-3(y-4)=2(y-5)

Solution for 9(y+7)-3(y-4)=2(y-5) equation:

9(y+7)-3(y-4)=2(y-5)

We move all terms to the left:

9(y+7)-3(y-4)-(2(y-5))=0

We multiply parentheses

9y-3y-(2(y-5))+63+12=0


We calculate terms in parentheses: -(2(y-5)), so:

2(y-5)

We multiply parentheses

2y-10

Back to the equation:

-(2y-10)


We add all the numbers together, and all the variables

6y-(2y-10)+75=0

We get rid of parentheses

6y-2y+10+75=0

We add all the numbers together, and all the variables

4y+85=0

We move all terms containing y to the left, all other terms to the right

4y=-85

y=-85/4

y=-21+1/4