9(y+7)-4(y-3)=2(y-4)

Solution for 9(y+7)-4(y-3)=2(y-4) equation:

9(y+7)-4(y-3)=2(y-4)

We move all terms to the left:

9(y+7)-4(y-3)-(2(y-4))=0

We multiply parentheses

9y-4y-(2(y-4))+63+12=0


We calculate terms in parentheses: -(2(y-4)), so:

2(y-4)

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)


We add all the numbers together, and all the variables

5y-(2y-8)+75=0

We get rid of parentheses

5y-2y+8+75=0

We add all the numbers together, and all the variables

3y+83=0

We move all terms containing y to the left, all other terms to the right

3y=-83

y=-83/3

y=-27+2/3