9(y+8)-2(y-4)=3(y-3)

Solution for 9(y+8)-2(y-4)=3(y-3) equation:

9(y+8)-2(y-4)=3(y-3)

We move all terms to the left:

9(y+8)-2(y-4)-(3(y-3))=0

We multiply parentheses

9y-2y-(3(y-3))+72+8=0


We calculate terms in parentheses: -(3(y-3)), so:

3(y-3)

We multiply parentheses

3y-9

Back to the equation:

-(3y-9)


We add all the numbers together, and all the variables

7y-(3y-9)+80=0

We get rid of parentheses

7y-3y+9+80=0

We add all the numbers together, and all the variables

4y+89=0

We move all terms containing y to the left, all other terms to the right

4y=-89

y=-89/4

y=-22+1/4