9(y-1)=6(y+2)-y

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Solution for 9(y-1)=6(y+2)-y equation: 



9(y-1)=6(y+2)-y

We move all terms to the left:

9(y-1)-(6(y+2)-y)=0

We multiply parentheses

9y-(6(y+2)-y)-9=0



We calculate terms in parentheses: -(6(y+2)-y), so:

6(y+2)-y

We add all the numbers together, and all the variables

-1y+6(y+2)

We multiply parentheses

-1y+6y+12

We add all the numbers together, and all the variables

5y+12

Back to the equation:

-(5y+12)



We get rid of parentheses

9y-5y-12-9=0

We add all the numbers together, and all the variables

4y-21=0

We move all terms containing y to the left, all other terms to the right

4y=21

y=21/4

y=5+1/4

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