9(y-2)=2(4y+5)-28

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Solution for 9(y-2)=2(4y+5)-28 equation: 



9(y-2)=2(4y+5)-28

We move all terms to the left:

9(y-2)-(2(4y+5)-28)=0

We multiply parentheses

9y-(2(4y+5)-28)-18=0



We calculate terms in parentheses: -(2(4y+5)-28), so:

2(4y+5)-28

We multiply parentheses

8y+10-28

We add all the numbers together, and all the variables

8y-18

Back to the equation:

-(8y-18)



We get rid of parentheses

9y-8y+18-18=0

We add all the numbers together, and all the variables

y=0

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