9(y-2)=6(y-1)-3y

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Solution for 9(y-2)=6(y-1)-3y equation: 



9(y-2)=6(y-1)-3y

We move all terms to the left:

9(y-2)-(6(y-1)-3y)=0

We multiply parentheses

9y-(6(y-1)-3y)-18=0



We calculate terms in parentheses: -(6(y-1)-3y), so:

6(y-1)-3y

We add all the numbers together, and all the variables

-3y+6(y-1)

We multiply parentheses

-3y+6y-6

We add all the numbers together, and all the variables

3y-6

Back to the equation:

-(3y-6)



We get rid of parentheses

9y-3y+6-18=0

We add all the numbers together, and all the variables

6y-12=0

We move all terms containing y to the left, all other terms to the right

6y=12

y=12/6

y=2

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