9(y-3)=-6y-42

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Solution for 9(y-3)=-6y-42 equation: 



9(y-3)=-6y-42

We move all terms to the left:

9(y-3)-(-6y-42)=0

We multiply parentheses

9y-(-6y-42)-27=0

We get rid of parentheses

9y+6y+42-27=0

We add all the numbers together, and all the variables

15y+15=0

We move all terms containing y to the left, all other terms to the right

15y=-15

y=-15/15

y=-1

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