9(y-4)-7y=6(3y-2)

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Solution for 9(y-4)-7y=6(3y-2) equation: 



9(y-4)-7y=6(3y-2)

We move all terms to the left:

9(y-4)-7y-(6(3y-2))=0

We add all the numbers together, and all the variables

-7y+9(y-4)-(6(3y-2))=0

We multiply parentheses

-7y+9y-(6(3y-2))-36=0



We calculate terms in parentheses: -(6(3y-2)), so:

6(3y-2)

We multiply parentheses

18y-12

Back to the equation:

-(18y-12)



We add all the numbers together, and all the variables

2y-(18y-12)-36=0

We get rid of parentheses

2y-18y+12-36=0

We add all the numbers together, and all the variables

-16y-24=0

We move all terms containing y to the left, all other terms to the right

-16y=24

y=24/-16

y=-1+1/2

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