9(y-4)=-10(y+6/3)

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Solution for 9(y-4)=-10(y+6/3) equation:



9(y-4)=-10(y+6/3)
We move all terms to the left:
9(y-4)-(-10(y+6/3))=0
We add all the numbers together, and all the variables
9(y-4)-(-10(y+2))=0
We multiply parentheses
9y-(-10(y+2))-36=0
We calculate terms in parentheses: -(-10(y+2)), so:
-10(y+2)
We multiply parentheses
-10y-20
Back to the equation:
-(-10y-20)
We get rid of parentheses
9y+10y+20-36=0
We add all the numbers together, and all the variables
19y-16=0
We move all terms containing y to the left, all other terms to the right
19y=16
y=16/19
y=16/19

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