9(y-4)=-10(y+6/3)

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Solution for 9(y-4)=-10(y+6/3) equation: 



9(y-4)=-10(y+6/3)

We move all terms to the left:

9(y-4)-(-10(y+6/3))=0

We add all the numbers together, and all the variables

9(y-4)-(-10(y+2))=0

We multiply parentheses

9y-(-10(y+2))-36=0



We calculate terms in parentheses: -(-10(y+2)), so:

-10(y+2)

We multiply parentheses

-10y-20

Back to the equation:

-(-10y-20)



We get rid of parentheses

9y+10y+20-36=0

We add all the numbers together, and all the variables

19y-16=0

We move all terms containing y to the left, all other terms to the right

19y=16

y=16/19

y=16/19

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