9(y-4)=3y+12

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Solution for 9(y-4)=3y+12 equation: 



9(y-4)=3y+12

We move all terms to the left:

9(y-4)-(3y+12)=0

We multiply parentheses

9y-(3y+12)-36=0

We get rid of parentheses

9y-3y-12-36=0

We add all the numbers together, and all the variables

6y-48=0

We move all terms containing y to the left, all other terms to the right

6y=48

y=48/6

y=8

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