9(z+1)-2(z-2)=2(z-2)+4(z-1)

Solution for 9(z+1)-2(z-2)=2(z-2)+4(z-1) equation:

9(z+1)-2(z-2)=2(z-2)+4(z-1)

We move all terms to the left:

9(z+1)-2(z-2)-(2(z-2)+4(z-1))=0

We multiply parentheses

9z-2z-(2(z-2)+4(z-1))+9+4=0


We calculate terms in parentheses: -(2(z-2)+4(z-1)), so:

2(z-2)+4(z-1)

We multiply parentheses

2z+4z-4-4

We add all the numbers together, and all the variables

6z-8

Back to the equation:

-(6z-8)


We add all the numbers together, and all the variables

7z-(6z-8)+13=0

We get rid of parentheses

7z-6z+8+13=0

We add all the numbers together, and all the variables

z+21=0

We move all terms containing z to the left, all other terms to the right

z=-21