9(z+1)-2(z-3)=3(z-3)+3(z-2)

Solution for 9(z+1)-2(z-3)=3(z-3)+3(z-2) equation:

9 (z+1)-2 (z-3)=3 (z-3)+3 (z-2)

We simplify the equation to the form, which is simple to understand 
9(z+1)-2(z-3)=3(z-3)+3(z-2)

Reorder the terms in parentheses
+(+9z+9)-2*(z-3)=3*(z-3)+3*(z-2)

Remove unnecessary parentheses
+9z+9-2+*(+z-3+)=+3+*(+z-3+)+3+*(+z-2+)

Reorder the terms in parentheses
+9z+9+(-2z+6)=3*(z-3)+3*(z-2)

Remove unnecessary parentheses
+9z+9-2z+6=+3+*(+z-3+)+3+*(+z-2+)

Reorder the terms in parentheses
+9z+9-2z+6=+(+3z-9)+3*(z-2)

Remove unnecessary parentheses
+9z+9-2z+6=+3z-9+3+*(+z-2+)

Reorder the terms in parentheses
+9z+9-2z+6=+3z-9+(+3z-6)

Remove unnecessary parentheses
+9z+9-2z+6=+3z-9+3z-6

We move all terms containing z to the left and all other terms to the right. 
+9z-2z-3z-3z=-9-6-9-6

We simplify left and right side of the equation. 
+1z=-30

We divide both sides of the equation by 1 to get z. 
z=-30