9(z+1)-3(z-1)=2(z-1)+3(z-4)

Solution for 9(z+1)-3(z-1)=2(z-1)+3(z-4) equation:

9(z+1)-3(z-1)=2(z-1)+3(z-4)

We move all terms to the left:

9(z+1)-3(z-1)-(2(z-1)+3(z-4))=0

We multiply parentheses

9z-3z-(2(z-1)+3(z-4))+9+3=0


We calculate terms in parentheses: -(2(z-1)+3(z-4)), so:

2(z-1)+3(z-4)

We multiply parentheses

2z+3z-2-12

We add all the numbers together, and all the variables

5z-14

Back to the equation:

-(5z-14)


We add all the numbers together, and all the variables

6z-(5z-14)+12=0

We get rid of parentheses

6z-5z+14+12=0

We add all the numbers together, and all the variables

z+26=0

We move all terms containing z to the left, all other terms to the right

z=-26