9(z+1)-3(z-2)=2(z-2)+3(z-3)

Solution for 9(z+1)-3(z-2)=2(z-2)+3(z-3) equation:

9(z+1)-3(z-2)=2(z-2)+3(z-3)

We move all terms to the left:

9(z+1)-3(z-2)-(2(z-2)+3(z-3))=0

We multiply parentheses

9z-3z-(2(z-2)+3(z-3))+9+6=0


We calculate terms in parentheses: -(2(z-2)+3(z-3)), so:

2(z-2)+3(z-3)

We multiply parentheses

2z+3z-4-9

We add all the numbers together, and all the variables

5z-13

Back to the equation:

-(5z-13)


We add all the numbers together, and all the variables

6z-(5z-13)+15=0

We get rid of parentheses

6z-5z+13+15=0

We add all the numbers together, and all the variables

z+28=0

We move all terms containing z to the left, all other terms to the right

z=-28