9(z+1)=5(z+5)

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Solution for 9(z+1)=5(z+5) equation:


Simplifying
9(z + 1) = 5(z + 5)

Reorder the terms:
9(1 + z) = 5(z + 5)
(1 * 9 + z * 9) = 5(z + 5)
(9 + 9z) = 5(z + 5)

Reorder the terms:
9 + 9z = 5(5 + z)
9 + 9z = (5 * 5 + z * 5)
9 + 9z = (25 + 5z)

Solving
9 + 9z = 25 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
9 + 9z + -5z = 25 + 5z + -5z

Combine like terms: 9z + -5z = 4z
9 + 4z = 25 + 5z + -5z

Combine like terms: 5z + -5z = 0
9 + 4z = 25 + 0
9 + 4z = 25

Add '-9' to each side of the equation.
9 + -9 + 4z = 25 + -9

Combine like terms: 9 + -9 = 0
0 + 4z = 25 + -9
4z = 25 + -9

Combine like terms: 25 + -9 = 16
4z = 16

Divide each side by '4'.
z = 4

Simplifying
z = 4

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