9(z+2)+6=96

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Solution for 9(z+2)+6=96 equation: 



9(z+2)+6=96

We move all terms to the left:

9(z+2)+6-(96)=0

We add all the numbers together, and all the variables

9(z+2)-90=0

We multiply parentheses

9z+18-90=0

We add all the numbers together, and all the variables

9z-72=0

We move all terms containing z to the left, all other terms to the right

9z=72

z=72/9

z=8

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