9(z+3)-2(z-4)=3(z-4)+3(z-1)

Solution for 9(z+3)-2(z-4)=3(z-4)+3(z-1) equation:

9(z+3)-2(z-4)=3(z-4)+3(z-1)

We simplify the equation to the form, which is simple to understand 
9(z+3)-2(z-4)=3(z-4)+3(z-1)

Reorder the terms in parentheses
+(+9z+27)-2*(z-4)=3*(z-4)+3*(z-1)

Remove unnecessary parentheses
+9z+27-2+*(+z-4+)=+3+*(+z-4+)+3+*(+z-1+)

Reorder the terms in parentheses
+9z+27+(-2z+8)=3*(z-4)+3*(z-1)

Remove unnecessary parentheses
+9z+27-2z+8=+3+*(+z-4+)+3+*(+z-1+)

Reorder the terms in parentheses
+9z+27-2z+8=+(+3z-12)+3*(z-1)

Remove unnecessary parentheses
+9z+27-2z+8=+3z-12+3+*(+z-1+)

Reorder the terms in parentheses
+9z+27-2z+8=+3z-12+(+3z-3)

Remove unnecessary parentheses
+9z+27-2z+8=+3z-12+3z-3

We move all terms containing z to the left and all other terms to the right. 
+9z-2z-3z-3z=-12-3-27-8

We simplify left and right side of the equation. 
+1z=-50

We divide both sides of the equation by 1 to get z. 
z=-50