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9(z+4)-2(z-1)=3(z-2)+3(z-3)
We move all terms to the left:
9(z+4)-2(z-1)-(3(z-2)+3(z-3))=0
We multiply parentheses
9z-2z-(3(z-2)+3(z-3))+36+2=0
We calculate terms in parentheses: -(3(z-2)+3(z-3)), so:We add all the numbers together, and all the variables
3(z-2)+3(z-3)
We multiply parentheses
3z+3z-6-9
We add all the numbers together, and all the variables
6z-15
Back to the equation:
-(6z-15)
7z-(6z-15)+38=0
We get rid of parentheses
7z-6z+15+38=0
We add all the numbers together, and all the variables
z+53=0
We move all terms containing z to the left, all other terms to the right
z=-53
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