9(z+4)-4(2+1)=2(z-1)+2(z-3)

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Solution for 9(z+4)-4(2+1)=2(z-1)+2(z-3) equation: 



9(z+4)-4(2+1)=2(z-1)+2(z-3)

We move all terms to the left:

9(z+4)-4(2+1)-(2(z-1)+2(z-3))=0

We add all the numbers together, and all the variables

9(z+4)-(2(z-1)+2(z-3))-43=0

We multiply parentheses

9z-(2(z-1)+2(z-3))+36-43=0



We calculate terms in parentheses: -(2(z-1)+2(z-3)), so:

2(z-1)+2(z-3)

We multiply parentheses

2z+2z-2-6

We add all the numbers together, and all the variables

4z-8

Back to the equation:

-(4z-8)



We add all the numbers together, and all the variables

9z-(4z-8)-7=0

We get rid of parentheses

9z-4z+8-7=0

We add all the numbers together, and all the variables

5z+1=0

We move all terms containing z to the left, all other terms to the right

5z=-1

z=-1/5

z=-1/5

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