9(z+4)=8(z-2)+z

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Solution for 9(z+4)=8(z-2)+z equation: 



9(z+4)=8(z-2)+z

We move all terms to the left:

9(z+4)-(8(z-2)+z)=0

We multiply parentheses

9z-(8(z-2)+z)+36=0



We calculate terms in parentheses: -(8(z-2)+z), so:

8(z-2)+z

We add all the numbers together, and all the variables

z+8(z-2)

We multiply parentheses

z+8z-16

We add all the numbers together, and all the variables

9z-16

Back to the equation:

-(9z-16)



We get rid of parentheses

9z-9z+16+36=0

We add all the numbers together, and all the variables

52!=0

There is no solution for this equation

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