9(z-12)=12z

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Solution for 9(z-12)=12z equation: 



9(z-12)=12z

We move all terms to the left:

9(z-12)-(12z)=0

We add all the numbers together, and all the variables

-12z+9(z-12)=0

We multiply parentheses

-12z+9z-108=0

We add all the numbers together, and all the variables

-3z-108=0

We move all terms containing z to the left, all other terms to the right

-3z=108

z=108/-3

z=-36

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