9(z-12)=12z

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Solution for 9(z-12)=12z equation:



9(z-12)=12z
We move all terms to the left:
9(z-12)-(12z)=0
We add all the numbers together, and all the variables
-12z+9(z-12)=0
We multiply parentheses
-12z+9z-108=0
We add all the numbers together, and all the variables
-3z-108=0
We move all terms containing z to the left, all other terms to the right
-3z=108
z=108/-3
z=-36

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