9(z-3)=2(z+1)

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Solution for 9(z-3)=2(z+1) equation:


Simplifying
9(z + -3) = 2(z + 1)

Reorder the terms:
9(-3 + z) = 2(z + 1)
(-3 * 9 + z * 9) = 2(z + 1)
(-27 + 9z) = 2(z + 1)

Reorder the terms:
-27 + 9z = 2(1 + z)
-27 + 9z = (1 * 2 + z * 2)
-27 + 9z = (2 + 2z)

Solving
-27 + 9z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-27 + 9z + -2z = 2 + 2z + -2z

Combine like terms: 9z + -2z = 7z
-27 + 7z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-27 + 7z = 2 + 0
-27 + 7z = 2

Add '27' to each side of the equation.
-27 + 27 + 7z = 2 + 27

Combine like terms: -27 + 27 = 0
0 + 7z = 2 + 27
7z = 2 + 27

Combine like terms: 2 + 27 = 29
7z = 29

Divide each side by '7'.
z = 4.142857143

Simplifying
z = 4.142857143

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