9(z-5)=6-(9z-55)

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Solution for 9(z-5)=6-(9z-55) equation: 



9(z-5)=6-(9z-55)

We move all terms to the left:

9(z-5)-(6-(9z-55))=0

We multiply parentheses

9z-(6-(9z-55))-45=0



We calculate terms in parentheses: -(6-(9z-55)), so:

6-(9z-55)

determiningTheFunctionDomain
-(9z-55)+6

We get rid of parentheses

-9z+55+6

We add all the numbers together, and all the variables

-9z+61

Back to the equation:

-(-9z+61)



We get rid of parentheses

9z+9z-61-45=0

We add all the numbers together, and all the variables

18z-106=0

We move all terms containing z to the left, all other terms to the right

18z=106

z=106/18

z=5+8/9

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