9*(2x+1)=5*(x-2)

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Solution for 9*(2x+1)=5*(x-2) equation: 



9(2x+1)=5(x-2)

We move all terms to the left:

9(2x+1)-(5(x-2))=0

We multiply parentheses

18x-(5(x-2))+9=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We get rid of parentheses

18x-5x+10+9=0

We add all the numbers together, and all the variables

13x+19=0

We move all terms containing x to the left, all other terms to the right

13x=-19

x=-19/13

x=-1+6/13

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