9*14=(x-4)(2x-4)

Solution for 9*14=(x-4)(2x-4) equation:

9*14=(x-4)(2x-4)

We move all terms to the left:

9*14-((x-4)(2x-4))=0

We add all the numbers together, and all the variables

-((x-4)(2x-4))+126=0

We multiply parentheses ..

-((+2x^2-4x-8x+16))+126=0


We calculate terms in parentheses: -((+2x^2-4x-8x+16)), so:

(+2x^2-4x-8x+16)

We get rid of parentheses

2x^2-4x-8x+16

We add all the numbers together, and all the variables

2x^2-12x+16

Back to the equation:

-(2x^2-12x+16)


We get rid of parentheses

-2x^2+12x-16+126=0

We add all the numbers together, and all the variables

-2x^2+12x+110=0

a = -2; b = 12; c = +110;
Δ = b2-4ac
Δ = 122-4·(-2)·110
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-32}{2*-2}=\frac{-44}{-4}
=+11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+32}{2*-2}=\frac{20}{-4}
=-5
$