9+(2x-2)3=(7+4x)1/5

Solution for 9+(2x-2)3=(7+4x)1/5 equation:

9+(2x-2)3=(7+4x)1/5

We move all terms to the left:

9+(2x-2)3-((7+4x)1/5)=0

We add all the numbers together, and all the variables

(2x-2)3-((4x+7)1/5)+9=0

We multiply parentheses

6x-((4x+7)1/5)-6+9=0

We multiply all the terms by the denominator


6x*5)-((4x+7)1-6*5)+9*5)=0

We add all the numbers together, and all the variables

6x*5)-((4x+7)1=0

Wy multiply elements

30x^2=0

a = 30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·30·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{60}=0$