9+(4-2x)-(1-x)=4x-2(x-3)

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Solution for 9+(4-2x)-(1-x)=4x-2(x-3) equation: 



9+(4-2x)-(1-x)=4x-2(x-3)

We move all terms to the left:

9+(4-2x)-(1-x)-(4x-2(x-3))=0

We add all the numbers together, and all the variables

(-2x+4)-(-1x+1)-(4x-2(x-3))+9=0

We get rid of parentheses

-2x+1x-(4x-2(x-3))+4-1+9=0



We calculate terms in parentheses: -(4x-2(x-3)), so:

4x-2(x-3)

We multiply parentheses

4x-2x+6

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

-1x-(2x+6)+12=0

We get rid of parentheses

-1x-2x-6+12=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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