9+(40/a-5)=(8a/a-5)

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Solution for 9+(40/a-5)=(8a/a-5) equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

40/a-5+9 = (8*a)/a-5 // - (8*a)/a-5

40/a-((8*a)/a)-5+5+9 = 0

40/a-8-5+5+9 = 0

40*a^-1 = -1 // : 40

a^-1 = -1/40

-1 < 0

1/(a^1) = -1/40 // * a^1

1 = -1/40*a^1 // : -1/40

-40 = a^1

a = -40

a = -40

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