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9+1/2x=8x+7
We move all terms to the left:
9+1/2x-(8x+7)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-8x-7+9=0
We multiply all the terms by the denominator
-8x*2x-7*2x+9*2x+1=0
Wy multiply elements
-16x^2-14x+18x+1=0
We add all the numbers together, and all the variables
-16x^2+4x+1=0
a = -16; b = 4; c = +1;
Δ = b2-4ac
Δ = 42-4·(-16)·1
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{5}}{2*-16}=\frac{-4-4\sqrt{5}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{5}}{2*-16}=\frac{-4+4\sqrt{5}}{-32} $
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