9+1=-1/2x-5x

Solution for 9+1=-1/2x-5x equation:

9+1=-1/2x-5x

We move all terms to the left:

9+1-(-1/2x-5x)=0


Domain of the equation: 2x-5x)!=0

x∈R


We add all the numbers together, and all the variables

-(-5x-1/2x)+9+1=0

We add all the numbers together, and all the variables

-(-5x-1/2x)+10=0

We get rid of parentheses

5x+1/2x+10=0

We multiply all the terms by the denominator


5x*2x+10*2x+1=0

Wy multiply elements

10x^2+20x+1=0

a = 10; b = 20; c = +1;
Δ = b2-4ac
Δ = 202-4·10·1
Δ = 360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-6\sqrt{10}}{2*10}=\frac{-20-6\sqrt{10}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+6\sqrt{10}}{2*10}=\frac{-20+6\sqrt{10}}{20}
$