9+2(4u-2)=-3(3u-1)+7u

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Solution for 9+2(4u-2)=-3(3u-1)+7u equation: 



9+2(4u-2)=-3(3u-1)+7u

We move all terms to the left:

9+2(4u-2)-(-3(3u-1)+7u)=0

We multiply parentheses

8u-(-3(3u-1)+7u)-4+9=0



We calculate terms in parentheses: -(-3(3u-1)+7u), so:

-3(3u-1)+7u

We add all the numbers together, and all the variables

7u-3(3u-1)

We multiply parentheses

7u-9u+3

We add all the numbers together, and all the variables

-2u+3

Back to the equation:

-(-2u+3)



We add all the numbers together, and all the variables

8u-(-2u+3)+5=0

We get rid of parentheses

8u+2u-3+5=0

We add all the numbers together, and all the variables

10u+2=0

We move all terms containing u to the left, all other terms to the right

10u=-2

u=-2/10

u=-1/5

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