9+2(4u-8)=-4(3u-2)+8u

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Solution for 9+2(4u-8)=-4(3u-2)+8u equation: 



9+2(4u-8)=-4(3u-2)+8u

We move all terms to the left:

9+2(4u-8)-(-4(3u-2)+8u)=0

We multiply parentheses

8u-(-4(3u-2)+8u)-16+9=0



We calculate terms in parentheses: -(-4(3u-2)+8u), so:

-4(3u-2)+8u

We add all the numbers together, and all the variables

8u-4(3u-2)

We multiply parentheses

8u-12u+8

We add all the numbers together, and all the variables

-4u+8

Back to the equation:

-(-4u+8)



We add all the numbers together, and all the variables

8u-(-4u+8)-7=0

We get rid of parentheses

8u+4u-8-7=0

We add all the numbers together, and all the variables

12u-15=0

We move all terms containing u to the left, all other terms to the right

12u=15

u=15/12

u=1+1/4

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