9+2(4v-3)=-2(5v-4)+8v

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Solution for 9+2(4v-3)=-2(5v-4)+8v equation: 



9+2(4v-3)=-2(5v-4)+8v

We move all terms to the left:

9+2(4v-3)-(-2(5v-4)+8v)=0

We multiply parentheses

8v-(-2(5v-4)+8v)-6+9=0



We calculate terms in parentheses: -(-2(5v-4)+8v), so:

-2(5v-4)+8v

We add all the numbers together, and all the variables

8v-2(5v-4)

We multiply parentheses

8v-10v+8

We add all the numbers together, and all the variables

-2v+8

Back to the equation:

-(-2v+8)



We add all the numbers together, and all the variables

8v-(-2v+8)+3=0

We get rid of parentheses

8v+2v-8+3=0

We add all the numbers together, and all the variables

10v-5=0

We move all terms containing v to the left, all other terms to the right

10v=5

v=5/10

v=1/2

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