9+2(5u-2)=-5(2u-3)+5u

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Solution for 9+2(5u-2)=-5(2u-3)+5u equation: 



9+2(5u-2)=-5(2u-3)+5u

We move all terms to the left:

9+2(5u-2)-(-5(2u-3)+5u)=0

We multiply parentheses

10u-(-5(2u-3)+5u)-4+9=0



We calculate terms in parentheses: -(-5(2u-3)+5u), so:

-5(2u-3)+5u

We add all the numbers together, and all the variables

5u-5(2u-3)

We multiply parentheses

5u-10u+15

We add all the numbers together, and all the variables

-5u+15

Back to the equation:

-(-5u+15)



We add all the numbers together, and all the variables

10u-(-5u+15)+5=0

We get rid of parentheses

10u+5u-15+5=0

We add all the numbers together, and all the variables

15u-10=0

We move all terms containing u to the left, all other terms to the right

15u=10

u=10/15

u=2/3

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