9+2(5w-3)=-3(2w-5)+7w

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Solution for 9+2(5w-3)=-3(2w-5)+7w equation: 



9+2(5w-3)=-3(2w-5)+7w

We move all terms to the left:

9+2(5w-3)-(-3(2w-5)+7w)=0

We multiply parentheses

10w-(-3(2w-5)+7w)-6+9=0



We calculate terms in parentheses: -(-3(2w-5)+7w), so:

-3(2w-5)+7w

We add all the numbers together, and all the variables

7w-3(2w-5)

We multiply parentheses

7w-6w+15

We add all the numbers together, and all the variables

w+15

Back to the equation:

-(w+15)



We add all the numbers together, and all the variables

10w-(w+15)+3=0

We get rid of parentheses

10w-w-15+3=0

We add all the numbers together, and all the variables

9w-12=0

We move all terms containing w to the left, all other terms to the right

9w=12

w=12/9

w=1+1/3

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