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9+2(x+4)-6x-5=8(3-x
We move all terms to the left:
9+2(x+4)-6x-5-(8(3-x)=0
We add all the numbers together, and all the variables
2(x+4)-6x-(8(-1x+3)+9-5=0
We add all the numbers together, and all the variables
-6x+2(x+4)-(8(-1x+3)+9-5=0
We multiply parentheses
-6x+2x-(8(-1x+3)+9-5+8=0
We add all the numbers together, and all the variables
-4x-(8(-1x+3)+9-5+8=0
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