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9+2(x-9)=10-5(x-6)
We move all terms to the left:
9+2(x-9)-(10-5(x-6))=0
We multiply parentheses
2x-(10-5(x-6))-18+9=0
We calculate terms in parentheses: -(10-5(x-6)), so:We add all the numbers together, and all the variables
10-5(x-6)
determiningTheFunctionDomain -5(x-6)+10
We multiply parentheses
-5x+30+10
We add all the numbers together, and all the variables
-5x+40
Back to the equation:
-(-5x+40)
2x-(-5x+40)-9=0
We get rid of parentheses
2x+5x-40-9=0
We add all the numbers together, and all the variables
7x-49=0
We move all terms containing x to the left, all other terms to the right
7x=49
x=49/7
x=7
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