9+2/3(6x-18)=3x-1/5(40-10x)

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Solution for 9+2/3(6x-18)=3x-1/5(40-10x) equation: 



9+2/3(6x-18)=3x-1/5(40-10x)

We move all terms to the left:

9+2/3(6x-18)-(3x-1/5(40-10x))=0



Domain of the equation: 3(6x-18)!=0

x∈R





Domain of the equation: 5(40-10x))!=0

x∈R



We add all the numbers together, and all the variables

2/3(6x-18)-(3x-1/5(-10x+40))+9=0

We calculate fractions


(10x(-)/(3(6x-18)*5(-10x+40)))+(-(3x-3x6)/(3(6x-18)*5(-10x+40)))+9=0



We calculate terms in parentheses: +(10x(-)/(3(6x-18)*5(-10x+40))), so:

10x(-)/(3(6x-18)*5(-10x+40))

We add all the numbers together, and all the variables

10x0/(3(6x-18)*5(-10x+40))

We multiply all the terms by the denominator


10x0

We add all the numbers together, and all the variables

10x

Back to the equation:

+(10x)





We calculate terms in parentheses: +(-(3x-3x6)/(3(6x-18)*5(-10x+40))), so:

-(3x-3x6)/(3(6x-18)*5(-10x+40))

We add all the numbers together, and all the variables

-(+3x-3x^6)/(3(6x-18)*5(-10x+40))

We multiply all the terms by the denominator


-(+3x-3x^6)

We do not support expression: x^6

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