9+2b-4(b+3)=11+b

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Solution for 9+2b-4(b+3)=11+b equation: 



9+2b-4(b+3)=11+b

We move all terms to the left:

9+2b-4(b+3)-(11+b)=0

We add all the numbers together, and all the variables

2b-4(b+3)-(b+11)+9=0

We multiply parentheses

2b-4b-(b+11)-12+9=0

We get rid of parentheses

2b-4b-b-11-12+9=0

We add all the numbers together, and all the variables

-3b-14=0

We move all terms containing b to the left, all other terms to the right

-3b=14

b=14/-3

b=-4+2/3

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