9+3(p+3)=3+p-4(p-2)

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Solution for 9+3(p+3)=3+p-4(p-2) equation:



9+3(p+3)=3+p-4(p-2)
We move all terms to the left:
9+3(p+3)-(3+p-4(p-2))=0
We multiply parentheses
3p-(3+p-4(p-2))+9+9=0
We calculate terms in parentheses: -(3+p-4(p-2)), so:
3+p-4(p-2)
determiningTheFunctionDomain p-4(p-2)+3
We multiply parentheses
p-4p+8+3
We add all the numbers together, and all the variables
-3p+11
Back to the equation:
-(-3p+11)
We add all the numbers together, and all the variables
3p-(-3p+11)+18=0
We get rid of parentheses
3p+3p-11+18=0
We add all the numbers together, and all the variables
6p+7=0
We move all terms containing p to the left, all other terms to the right
6p=-7
p=-7/6
p=-1+1/6

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