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9+3(x-2)=2+4(x-1)
We move all terms to the left:
9+3(x-2)-(2+4(x-1))=0
We multiply parentheses
3x-(2+4(x-1))-6+9=0
We calculate terms in parentheses: -(2+4(x-1)), so:We add all the numbers together, and all the variables
2+4(x-1)
determiningTheFunctionDomain 4(x-1)+2
We multiply parentheses
4x-4+2
We add all the numbers together, and all the variables
4x-2
Back to the equation:
-(4x-2)
3x-(4x-2)+3=0
We get rid of parentheses
3x-4x+2+3=0
We add all the numbers together, and all the variables
-1x+5=0
We move all terms containing x to the left, all other terms to the right
-x=-5
x=-5/-1
x=+5
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