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9+3/4v=v-9
We move all terms to the left:
9+3/4v-(v-9)=0
Domain of the equation: 4v!=0We get rid of parentheses
v!=0/4
v!=0
v∈R
3/4v-v+9+9=0
We multiply all the terms by the denominator
-v*4v+9*4v+9*4v+3=0
Wy multiply elements
-4v^2+36v+36v+3=0
We add all the numbers together, and all the variables
-4v^2+72v+3=0
a = -4; b = 72; c = +3;
Δ = b2-4ac
Δ = 722-4·(-4)·3
Δ = 5232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5232}=\sqrt{16*327}=\sqrt{16}*\sqrt{327}=4\sqrt{327}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-4\sqrt{327}}{2*-4}=\frac{-72-4\sqrt{327}}{-8} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+4\sqrt{327}}{2*-4}=\frac{-72+4\sqrt{327}}{-8} $
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